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a ∝ b
a = k(b);
removing the proportionality and adding the constant.
k = a / b
now, the above equation can be converted into two proportionality each keeping 'a' or 'b' constant respectively.
k ∝ 1 / b
keeping 'a' constant;
or
k ∝ a / 1
keeping 'b' constant;
let's take the equation with 'a' constant:
k ∝ 1 / b
as 'b' will approach '0', k will approach 'infinity';
b --> 0 , k --> ∞ ;
when b will become zero, k should become infinity;
∞ ∝ 1 / 0
or
∞ = 1 / 0 * a
or
∞ = a / 0
where 'a' is any positive number.
let's take the equation with 'b' constant:
k ∝ a / 1
keeping 'a' constant;
or
k ∝ a / 1
keeping 'b' constant;
let's take the equation with 'a' constant:
k ∝ 1 / b
as 'b' will approach '0', k will approach 'infinity';
b --> 0 , k --> ∞ ;
when b will become zero, k should become infinity;
∞ ∝ 1 / 0
or
∞ = 1 / 0 * a
or
∞ = a / 0
where 'a' is any positive number.
let's take the equation with 'b' constant:
k ∝ a / 1
or
k ∝ a
as 'a' will approach 'infinity', 'b' will also approach 'infinity';
a --> ∞ , k --> ∞ ;
when 'a' will become 'infinity' , 'k' should also become 'infinity';
∞ ∝ ∞
or
∞ = (b)∞
where 'b' is any positive number.
∞ = (b)∞ implies that multiplying any positive number with infinity will only result in infinity.
∞ = a / 0 implies that dividing any positive number by zero will only result in infinity.
comment below if you have any questions or simply to start a discussion.
as 'a' will approach 'infinity', 'b' will also approach 'infinity';
a --> ∞ , k --> ∞ ;
when 'a' will become 'infinity' , 'k' should also become 'infinity';
∞ ∝ ∞
or
∞ = (b)∞
where 'b' is any positive number.
∞ = (b)∞ implies that multiplying any positive number with infinity will only result in infinity.
∞ = a / 0 implies that dividing any positive number by zero will only result in infinity.
comment below if you have any questions or simply to start a discussion.
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